A,B&C are a running a see of 1000ms,A beat B by 200ms,B beat C by 200ms.Then A beat C by how masses meters?
Answers:
(1000/B)-(1000/A)=200/B
(1000/C)-(1000/B)=200/C
(1000/C)-(1000/A)=X/C
"X" is the answer in metres.
5A-5B=A
5B-5C=B
1000A-1000C=XA
4A=5B
4B=5C
4A=(25/4)C
640A=1000C
1000A-640A=XA
1000-640=X
X=360m/s
Related Questions:
