A forgiving next to a dislocated shoulder is put into a traction apparatus?

The pulls and have equal magnitudes and must combine to produce an outward traction force of 5.53 on the patient's arm how large should these pulls be? in Newtons. I can't numeral this out! help?
Answers:
I think there's some missing data on your give somebody the third degree. Maybe a diagram of the pulls.
You should overlook so if there's more than one string/force pulling, the RESULTING FORCE should be equal to 5.53 (Newtons?)

The resulting force can be calculated by the sum of all parallel vectors on the shoulder apparatus direction, each one given by F (co α), as in:

Resulting F (a+b+c) = Fa (cos α) + Fb (cos ss) + Fc (cos ) Source(s): I'm a physician and a Phisics enthusiast during college

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